On Sunday, December 15, 2024 at 2:28:26 AM UTC-7 Quentin Anciaux wrote:

Le dim. 15 déc. 2024, 10:12, Alan Grayson <[email protected]> a écrit :

On Sunday, December 15, 2024 at 1:51:21 AM UTC-7 Quentin Anciaux wrote:

Le dim. 15 déc. 2024, 09:40, Alan Grayson <[email protected]> a écrit :

On Saturday, December 14, 2024 at 11:27:37 PM UTC-7 Jesse Mazer wrote:

On Sat, Dec 14, 2024 at 10:46 PM Alan Grayson <[email protected]> wrote:

On Saturday, December 14, 2024 at 8:15:37 PM UTC-7 Jesse Mazer wrote:

On Sat, Dec 14, 2024 at 9:46 PM Alan Grayson <[email protected]> wrote:

On Saturday, December 14, 2024 at 2:16:36 PM UTC-7 Jesse Mazer wrote:

On Sat, Dec 14, 2024 at 12:34 PM Alan Grayson <[email protected]> wrote:

On Saturday, December 14, 2024 at 7:58:34 AM UTC-7 Jesse Mazer wrote:

On Sat, Dec 14, 2024 at 5:27 AM Alan Grayson <[email protected]> wrote:

On Saturday, December 14, 2024 at 1:35:54 AM UTC-7 Alan Grayson wrote:

On Friday, December 13, 2024 at 8:48:39 PM UTC-7 Brent Meeker wrote:

On 12/13/2024 7:02 PM, Alan Grayson wrote:

        On Friday, December 13, 2024 at 7:30:31 PM UTC-7 Brent Meeker wrote:

                        On 12/13/2024 3:09 PM, Alan Grayson wrote:

For some rest length frame parameters, there's a v, such that for 
velocities greater than v, won't the car fit in all garage frames, but in 
none of the car frames? If this is correct, what's the justification for 
saying the solution exists in one set of frames, but not in another? And 
what's the argument that in all of these frames, simultaneity of front and 
back of car is satisfied?  TY, AG

What could it possibly mean for the car *not to fit* in the car frame! 

*Have you ever tried to park a car? Use your brains and you'll figure it 
out. It's called the Lorentz Parking Paradox. You're trying to park a car 
of known rest length, in a garage of known rest length. Follow me so far? 
Now get the car moving and from the car's frame notice how the garage 
length Lorentz contracts. Follow me so far? At some v or greater, the 
length of the garage will be smaller than the car's rest length. When this 
happens most sane individuals will conclude that the car won't fit. *


*OK, you meant the car will not fit in the garage, in the car's frame. *

 


* Brent*


*Maybe, just maybe, this apparent paradox cannot be resolved by solely 
analyzing what happens in space, but in spacetime. Tomorrow I will make an 
effort to fully understand your spacetime diagrams and see if they shed any 
light on this issue. The clue might be the fact that in relativity, ds^2 is 
frame invariant. And FWIW, I haven't seen any convincing arguments based 
solely on the frame non-invariance of simultaneity. It's often claimed this 
non-invariance solves the problem, but detailed proofs are woefully 
lacking. AG*


*The reason a paradox seems to exist is because the frame observers witness 
contrary events; the garage observer sees the car fitting in the garage, 
whereas the car observer sees the car not fitting in the garage, when 
there's only one possible thing to observe. AG*


"Events" in relativity generally refer to things that happen at a single 
point in spacetime, like the back end of the car passing by the front of 
the garage with the clocks mounted to each showing particular readings; the 
different frames do not disagree about any localized events in this sense. 
Did you understand my point about why the question "did the car fit" 
reduces to the question "did the event A of the back of the car passing the 
front of the garage happen before the event B of the front of the car 
reaching the back of the garage"?

Jesse


*Yes. In relativity measurements are generally not frame invariant, such as 
the E and B fields in EM. But this case seems different. Imagine two 
observers, one in car frame and the other in garage frame, and they're both 
viewing the car passing through the garage, now open on both ends. 
Ostensibly, the former sees the car fail to fit in the garage, the latter 
sees the opposite. I don't believe a rigorous definition of "fit" will 
resolve this contradiction. *


Note that when we talk about what happens in a given frame this is not what 
any observer sees with their eyes, it's about when they judge various 
events to have happened once they factor out delays due to light transit 
time, or what times they assign events using local readings on synchronized 
clocks that were at the same position as the events when they occurred. For 
example, if in 2025 I see light from an event 5 light years away, and then 
on the same day and time in 2030 I see light from an event 10 light years 
away, I will say that in my frame both events happened simultaneously in 
2020, even though I did not see them simultaneously in a visual sense. And 
if I had a set of clocks throughout space that were synchronized in my 
frame, when looking through my telescope I'd see that the clocks next to 
both events showed the same date and time in 2000 when the events happened.

When you say 'I don't believe a rigorous definition of "fit" will resolve 
this contradiction', which of these is closer to your meaning?

1. If event A = "back of car passes through front door of garage" and B = 
"front of car reaches back of garage", then *even if* you grant that the 
question "does the car fit" is defined to be 100% equivalent to the 
question "does A happen before B", you still think an analysis of how 
simultaneity works in relativity which shows that the two frames can 
disagree about the order of A and B is *not* sufficient to resolve the 
paradox.


*I just wrote a more detailed reply and it was lost. Yes, if both frames 
disagree about car fitting, IMO paradox is alive and well. I assume 
observers in each frame view the same phenomenon, so regardless of what 
relativity claims, they must see the same thing. This is different from the 
general case of different frames making different measurements, but I can't 
precisely explain in this case, the distinction between these two types of 
measurements. AG *


They see exactly the same local events. As I said before, if there are a 
pair of clocks attached to either end of the garage which are synchronized 
in the garage frame, and a pair of clocks attached to either end of the car 
which are synchronized in the car frame, then in Brent's example they both 
see that when the back of the car passes the front of the garage (event A), 
the back car clock and front garage clock both read 0; and when the front 
of the car reaches the back of the garage (event B), the front car clock 
reads -7.5 and the back garage clock reads 3.5. The only difference is the 
*convention* each frame adopts about which clocks are synchronized--the car 
frame calls the car clocks "synchronized" and the garage clocks 
"out-of-sync", and the garage frame calls the garage clocks "synchronized" 
and the car clocks "out of sync". Thus, based on their different 
conventions, the car frame says the event A happened later than event B (A 
at time 0, B at time -7.5), and the garage frame says the event A happened 
earlier than event B (A at time 0, B at time 3.5).

Consider an analogy with disagreements about spatial coordinates. Say there 
is a post on the ground, and two observers both define the x-axis of their 
respective coordinate systems by rulers which touch the post, but the two 
observers place the x=0 mark of their respective rulers 2 meters apart from 
one another, so that the post is next to the 3 meter mark on the ruler of 
observer #1, and next to the 5 meter mark on the ruler of observer #2. The 
only difference is that they have different *conventions* for defining the 
x-coordinate of objects on the ground, with each one defining x-coordinate 
by markings on their own ruler. There is no disagreement about the fact 
that the post is next to the 3 meter mark of observer #1's ruler and next 
to the 5 meter mark of observer #2's ruler, but because of their different 
conventions, this means observer #1 says "the post has position x=3 meters" 
and observer #2 says "the post has position x=5 meters". Do you think this 
is some deep physical contradiction, or would you agree it's a mere 
difference in the convention used about which ruler to use when assigning 
x-coordinates? If the latter, then why do you think the situation with the 
garage and car is any different? All observers agree about what all 
specific physical clocks read at event A and B, they merely differ on their 
respective conventions about which clocks to use to assign t-coordinates to 
events A and B. 


2. You grant that there is a good explanation for why different frames can 
disagree about the order of A and B, 

but you have an argument or strong intuition that the question "does A 
happen before B" is *not* equivalent in meaning to "does the car fit in the 
garage"


*Not sure how to answer your question. I haven't thought about ordering. 
Nonetheless, any disagreement about whether car fits means the paradox is 
alive and well. AG *


You haven't thought about it?? Disagreement about the ordering of these two 
specific events (due to differences in simultaneity) is what Brent and I 
have both been emphasizing as the fundamental resolution of the paradox, 
have you not even understood that this is central to what we are arguing, 
and considered in an open-minded way whether or not it makes sense?


*I meant I hadn't considered the ordering you postulated as effecting 
simultaneity. By "fit", I always meant the ordering you described, and that 
the paradox is alive and well under such ordering. *


By "the paradox is alive and well" do you just mean that the car rest frame 
and the garage rest frame disagree about the order of those events A and B?


*IIRC, I never discussed order of events; just contraction of lengths from 
different frames. I thought it paradoxical that the frames could disagree 
on whether the car could fit or not (and Brent gave the conditions for a 
fit in a recent post). Now I am not so sure. Maybe the frames can disagree 
about whether the car fits, and there's no problem. That seems to be the 
consensus view on this MB and elsewhere. AG*


Please define fits into ? Fitting means the following two events are 
simultaneous: the rear of the car is at or after the entrance while 
simultaneously the front of the car is before or at the exit... so this 
clearly depends on simultaneity... if you don't get it, then I think it’s 
impossible to fit this idea in your brean whatever speed and enlarged 
contraction factor applied to it.


*Firstly, I really don't need your snotty attitude. So, clean up your act 
or STFU. FWIW, I know what simultaneity is, but what I'm not sure about is 
how it allegedly solves the problem, if there is one, of the frames 
disagreeing about whether the car fits in the garage. AG*


Do you or not agree with the definition of fitting into ? If yes, do you 
see how it involves simultaneity? If you disagree, please define fits into 
without using simultaneity. 


I agree. AG 

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