On 12/15/2024 10:44 PM, Alan Grayson wrote:
But in *every* frame the front of the car passes thru the front the garage before the rear; so ultimately affirming that means nothing except the car is going forward, not in reverse. But you couldn't think a moment and figure that out. Instead you rush to your keyboard to write so more questions.*So if front and back of car pass through front of garage in that order*, that's not enough to affirm fitness and/or simultaneity? And if simultaneity is ultimately affirmed, will ALL other frames have the time order reversed? TY, AGC'mon Alan stop playing dumb. It's obvious that driving a car thru at any speed (except "reverse") has the front and back of the car pass through front of garage in that order (and also pass thru the back of the garage in that order); it's a fact that arises because the front of the car precedes the back of the car down the road.*Actually, you're the one who's playing dumb. Or maybe you are dumb. Or maybe you have poor command of English. Suggest you read what you wrote, CAREFULLY! You claimed, and Jesse affirmed, that even when the car fits in the garage, and the ends are measured as simultaneous, there are frames where the two end events (front and back) are simultaneous, and frames where they are not simultaneous. *
Brent
*So, it is logical to infer from your statement that there could be two events in some frame, that might or might not be simultaneous, in the absense of fitting. Physicists are not expected to be masters of language, but your understanding of your own words doesn't meet grade school level. AG*
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