Tried uninstall and did a new install using branches v. 2.1 @3546 but I get the same result...
Tomorrow I'll try a completely clean install of python, fipy and all packages on another pc.... Thanks > Date: Tue, 18 May 2010 18:46:05 -0400 > From: [email protected] > To: [email protected] > Subject: Re: Problem in solving Poisson equation with 1D Cylindrical mesh > > > Make that branches/version-2_1 rather than trunk/. > > On Tue, May 18, 2010 at 5:28 PM, Daniel Wheeler > <[email protected]> wrote: > > > > It might be easier to do a fresh checkout of trunk rather than copying > > files around. > > > > What happens if you put a print statement here > > <http://matforge.org/fipy/browser/trunk/fipy/meshes/numMesh/cylindricalGrid1D.py#L78>? > > The method wasn't in the older version.. > > > > On Tue, May 18, 2010 at 3:37 PM, Eduard Manley <celez1...@hotmailcom> wrote: > >> I get again the first one.... > >> As said before I copied the files in the dir fipy/meshes/numMesh and did a > >> new install. It's wrong or there is something else.... > >> > >> Thanks > >> > >>> Date: Mon, 17 May 2010 10:10:45 -0400 > >>> From: [email protected] > >>> To: [email protected] > >>> Subject: Re: Problem in solving Poisson equation with 1D Cylindrical mesh > >>> > >>> > >>> An older version of fipy (tr...@3480, for example) gives, > >>> > >>> In [1]: from fipy import * > >>> m = CylindricalGrid1D(dx=(1.,2.)) > >>> > >>> /users/wd15/Documents/python/fipy/tr...@3480/fipy/viewers/gnuplotViewer/gnuplot1DViewer.py:76: > >>> Warning: 'with' will become a reserved keyword in Python 2.6 > >>> In [2]: m = CylindricalGrid1D(dx=(1.,2.)) > >>> In [3]: > >>> In [4]: > >>> In [5]: m.getCellVolumes() > >>> Out[5]: array([ 0.5, 16. ]) > >>> > >>> The latest version of trunk gives, > >>> > >>> In [1]: from fipy import * > >>> In [2]: m = CylindricalGrid1D(dx=(1.,2.)) > >>> In [3]: m.getCellVolumes() > >>> Out[3]: array([ 0.5, 4. ]) > >>> > >>> What do you get? > >>> > >>> On Sun, May 16, 2010 at 2:52 PM, Eduard Manley <[email protected]> > >>> wrote: > >>> > Hi, > >>> > thanks for your reply. > >>> > > >>> > I copied the files in the install dir (right subdir) and did a new > >>> > install > >>> > of fipy (completely new install on other pc), it should be ok but I > >>> > tried > >>> > running the code and the result is the same as before and so is wrong. > >>> > > >>> > I am doing some error? > >>> > > >>> > Thanks > >>> > > >>> >> Date: Thu, 13 May 2010 16:51:39 -0400 > >>> >> From: [email protected] > >>> >> To: [email protected] > >>> >> Subject: Re: Problem in solving Poisson equation with 1D Cylindrical > >>> >> mesh > >>> >> > >>> >> > >>> >> With any luck this has now been dealt with. Latest versions of > >>> >> branches/version-2_1 and trunk/ should now have the fixes for > >>> >> <http://matforge.org/fipy/ticket/294> > >>> >> > >>> >> On Tue, May 11, 2010 at 5:44 PM, Eduard Manley <[email protected]> > >>> >> wrote: > >>> >> > Hi, > >>> >> > thanks for your reply. > >>> >> > > >>> >> > You can find attached a sample problem. > >>> >> > > >>> >> > The equation is a heat equation, variable is temperature,other and > >>> >> > transient > >>> >> > and diffusion term, there is a spatially varying source term (q) > >>> >> > computed > >>> >> > by analytical expression which is and hyperbola. > >>> >> > > >>> >> > We should reach about 100°C in 30-35 sec and the shape of the > >>> >> > solution > >>> >> > should be similiar to and hyperbola. > >>> >> > > >>> >> > As it is now the file works fine (mesh declared with: mesh = > >>> >> > CylindricalGrid1D(dr=dr, nr=(len(DR))) + (r_int,) ) but if you define > >>> >> > the > >>> >> > mesh with ( mesh = CylindricalGrid1D(dx=DR) + (r_int,) ) the result > >>> >> > you > >>> >> > obtain are wrong. > >>> >> > > >>> >> > The 2 declaration of CylindricalGrid1D should be the same, the face > >>> >> > and > >>> >> > cell > >>> >> > centers are the same, but the result are different. > >>> >> > > >>> >> > You can observe the same problem also when solving the same equation > >>> >> > but without transient term > >>> >> > > >>> >> > Thanks > >>> >> > Eduard > >>> >> > > >>> >> > > >>> >> > > >>> >> >> Date: Tue, 11 May 2010 10:45:24 -0400 > >>> >> >> From: [email protected] > >>> >> >> To: [email protected] > >>> >> >> Subject: Re: Problem in solving Poisson equation with 1D Cylindrical > >>> >> >> mesh > >>> >> >> > >>> >> >> > >>> >> >> Can you put together the simplest script possible that demonstrates > >>> >> >> the problem and I'll try and debug it? Thanks. > >>> >> >> > >>> >> >> On Thu, May 6, 2010 at 2:01 PM, Eduard Manley > >>> >> >> <[email protected]> > >>> >> >> wrote: > >>> >> >> > Thanks for your reply. > >>> >> >> > > >>> >> >> > I probably found the reason of the problem. > >>> >> >> > > >>> >> >> > As said before I'm trying to solve an eq of this type: > >>> >> >> > > >>> >> >> > A(d phi/d t) = div (D grad phi) + q > >>> >> >> > > >>> >> >> > where A and D are costant coefficient and q is a spatially varying > >>> >> >> > heat > >>> >> >> > source. > >>> >> >> > > >>> >> >> > The problem is in how I create the cylindrical 1D mesh (origin of > >>> >> >> > the > >>> >> >> > mesh > >>> >> >> > is not in 0.). > >>> >> >> > > >>> >> >> > It doesn't matter if the discretization is logarithmic or uniform > >>> >> >> > but > >>> >> >> > how I > >>> >> >> > declare it: > >>> >> >> > > >>> >> >> > (using a uniform spacing:) > >>> >> >> > > >>> >> >> > ** mesh = CylindricalGrid1D(dx=dr, nx=(len(DR))) + (r_int,) ** > >>> >> >> > SHOULD BE EQUAL TO: > >>> >> >> > > >>> >> >> > ** mesh = CylindricalGrid1D(dx=DR) + (r_int,) ** > >>> >> >> > > >>> >> >> > [dr = 5e-04, nr=58, r_int=0.00125, DR is a list which contains the > >>> >> >> > various > >>> >> >> > dx(58 elements of value dr for uniform grid)] > >>> >> >> > > >>> >> >> > BUT It is NOT. > >>> >> >> > > >>> >> >> > The mesh (cell centers, facecenters) is ok but the results are > >>> >> >> > NOT. > >>> >> >> > The results are right only if I create the mesh using dx=dr and > >>> >> >> > nx=. > >>> >> >> > . > >>> >> >> > And this is why before I thought the problem was the logaritmic > >>> >> >> > discretization (must use DR=[...]). > >>> >> >> > > >>> >> >> > As said before with Cylindrical 2D mesh results are > >>> >> >> > instead correct. > >>> >> >> > Is this a bug? > >>> >> >> > > >>> >> >> >> Date: Thu, 6 May 2010 11:11:10 -0400 > >>> >> >> >> From: [email protected] > >>> >> >> >> To: [email protected] > >>> >> >> >> Subject: Re: Problem in solving Poisson equation with 1D > >>> >> >> >> Cylindrical > >>> >> >> >> mesh > >>> >> >> >> > >>> >> >> >> > >>> >> >> >> Edward, This may be to do with having a very small volume (or > >>> >> >> >> area > >>> >> >> >> or > >>> >> >> >> line or point) for the inner most element of the domain. It > >>> >> >> >> should > >>> >> >> >> be > >>> >> >> >> the same whether one is using a 1D or 2D mesh. Since you are > >>> >> >> >> getting > >>> >> >> >> differences in the 1D and 2D case, it should be relatively easy > >>> >> >> >> to > >>> >> >> >> debug and figure out what's going on It could also be that the > >>> >> >> >> boundary condition on the inner boundary as zero area and this is > >>> >> >> >> causing issues. Try shifting the grid by a small value away from > >>> >> >> >> the > >>> >> >> >> zero point and see if things are improved I have always had this > >>> >> >> >> issue with cylindrical grids and have never really had a > >>> >> >> >> satisfactory > >>> >> >> >> solution (other than shifting away from the zero point). If you > >>> >> >> >> discover a better way to handle this, let me know. Cheers. > >>> >> >> >> > >>> >> >> >> > >>> >> >> >> If you can't debug it, then send me the most minimalist scripts > >>> >> >> >> that > >>> >> >> >> show the issue and I'll give it a shot. > >>> >> >> >> > >>> >> >> >> On Wed, May 5, 2010 at 9:53 PM, Eduard Manley > >>> >> >> >> <[email protected]> > >>> >> >> >> wrote: > >>> >> >> >> > Problem partially solved: > >>> >> >> >> > > >>> >> >> >> > I'm using a logarithmic discretization (first dr= 5e-04 and > >>> >> >> >> > next > >>> >> >> >> > dr increasing as 1.05)(with internal radius= 0.00125, external > >>> >> >> >> > radius=0.03) > >>> >> >> >> > and, > >>> >> >> >> > for some unknown reason this create problems and wrong > >>> >> >> >> > result with > >>> >> >> >> > cylindrical 1D mesh. I tried using a uniform discretization > >>> >> >> >> > (dr=5e-04 > >>> >> >> >> > nx=58) > >>> >> >> >> > and now the result is correct. > >>> >> >> >> > > >>> >> >> >> > However I need to use the logarithmic discr. so after some > >>> >> >> >> > hours > >>> >> >> >> > of > >>> >> >> >> > sleep > >>> >> >> >> > I'll think about the reason..... > >>> >> >> >> > > >>> >> >> >> > ________________________________ > >>> >> >> >> > Hotmail: Trusted email with powerful SPAM protection. Sign up > >>> >> >> >> > now. > >>> >> >> >> > >>> >> >> >> > >>> >> >> >> > >>> >> >> >> -- > >>> >> >> >> Daniel Wheeler > >>> >> >> >> > >>> >> >> >> > >>> >> >> > > >>> >> >> > ________________________________ > >>> >> >> > Your E-mail and More On-the-Go. Get Windows Live Hotmail Free Sign > >>> >> >> > up > >>> >> >> > now. > >>> >> >> > >>> >> >> > >>> >> >> > >>> >> >> -- > >>> >> >> Daniel Wheeler > >>> >> >> > >>> >> >> > >>> >> > > >>> >> > ________________________________ > >>> >> > Hotmail: Trusted email with Microsoft’s powerful SPAM protection. > >>> >> > Sign > >>> >> > up > >>> >> > now. > >>> >> > >>> >> > >>> >> > >>> >> -- > >>> >> Daniel Wheeler > >>> >> > >>> >> > >>> > > >>> > > >>> > ________________________________ > >>> > Hotmail: Free, trusted and rich email service. Get it now > >>> > >>> > >>> > >>> -- > >>> Daniel Wheeler > >>> > >>> > >> > >> ________________________________ > >> Hotmail: Powerful Free email with security by Microsoft. Get it now. > > > > > > > > -- > > Daniel Wheeler > > > > > > > > > > -- > Daniel Wheeler > > _________________________________________________________________ Hotmail: Trusted email with powerful SPAM protection. https://signup.live.com/signup.aspx?id=60969
