26.03.2013 7:42, Dmitry Yemanov wrote: > This was an intended change which probably became an overkill. I will > report back after closer investigation.
Sorry, I thought that your issue was caused by the i.RDB$RELATION_NAME = rf.RDB$RELATION_NAME condition, but it's not. So there's only one error and it's explained in my prior message. No bugs here, everything is as designed. The query should be rewritten as: select rf.RDB$RELATION_NAME, rf.RDB$FIELD_NAME, s.RDB$INDEX_NAME from RDB$RELATION_FIELDS rf left join ( RDB$INDICES i join RDB$INDEX_SEGMENTS s on i.RDB$INDEX_NAME = s.RDB$INDEX_NAME join RDB$RELATION_CONSTRAINTS rc on rc.RDB$INDEX_NAME = s.RDB$INDEX_NAME and rc.RDB$CONSTRAINT_TYPE = 'FOREIGN KEY' ) on i.RDB$RELATION_NAME = rf.RDB$RELATION_NAME and s.RDB$FIELD_NAME = rf.RDB$FIELD_NAME where rf.RDB$FIELD_SOURCE starting with 'D_FK_' Dmitry ------------------------------------------------------------------------------ Own the Future-Intel® Level Up Game Demo Contest 2013 Rise to greatness in Intel's independent game demo contest. Compete for recognition, cash, and the chance to get your game on Steam. $5K grand prize plus 10 genre and skill prizes. Submit your demo by 6/6/13. http://p.sf.net/sfu/intel_levelupd2d Firebird-Devel mailing list, web interface at https://lists.sourceforge.net/lists/listinfo/firebird-devel