Hi,
first, thank you!
But it should only delete the right *
For example, the ID is ABCDEFG, the interface will tell me ABCDEFG*********01
In this case, from right, all * should deleted.
But If the ID is ABC*DEFG, I get ABC*DEFG********01 and in this case only all *
from right should be deleted.
I have create this, is there a simpler way?
begin
str = left(:str,16); -- only 16 digits, the other I don’t use here
while (k = 1) do
begin
if(right(str, 1) = '*') then
begin
str = left(str,char_length(str)-1);
end
else
begin
teil = str;
k = 0;
end
end
end
Von: firebird-support@yahoogroups.com [mailto:firebird-support@yahoogroups.com]
Gesendet: Montag, 7. Dezember 2015 09:56
An: firebird-support@yahoogroups.com
Betreff: Re: [firebird-support] string difficulty
How can I get ABC*DEFG, leave the * between C*D, delete all * from right?
SET TERM ^ ;
CREATE PROCEDURE DEL_CHAR (
M_SIR varchar(500),
M_CHAR varchar(10) )
RETURNS (
M_STR varchar(500) )
AS
declare ii smallint;
declare iy smallint;
BEGIN
m_str='';
iy=char_length(m_sir);
ii=1;
while (ii<=iy) do
begin
if (position(substring(m_sir from ii for 1),m_char)=0) then
m_str=m_str||substring(m_sir from ii for 1);
ii=ii+1;
end
END^
SET TERM ; ^
m_sir='ABC*DEFG'
m_char='*'
