But in this case The comparision should be for two chars
while (ii<=iy) do
begin
if (position(substring(m_sir from ii for 2),m_char)=0) then
m_str=m_str||substring(m_sir from ii for 1);
ii=ii+1;
end
But, if the original ID like TEIL***ABC Then will be the three *** deletet,
only the right * should be cut, this are the * who filled…
Von: [email protected] [mailto:[email protected]]
Gesendet: Montag, 7. Dezember 2015 11:22
An: [email protected]
Betreff: Re: AW: [firebird-support] string difficulty
a quick answer :
m_char='**'
On Monday, December 7, 2015 12:12 PM, "'checkmail'
<mailto:[email protected]> [email protected] [firebird-support]" <
<mailto:[email protected]> [email protected]>
wrote:
But If the ID is ABC*DEFG, I get ABC*DEFG********01 and in this case only all *
from right should be deleted.
I have create this, is there a simpler way?
