You can use this syntax:
function compose (fn1, fn2) {
// returns a function that calls fn1 with the result of fn2
function inner() {
return fn1( fn2.apply(null, arguments))
}
return inner;
}
This is perfectly valid javascript and will do exactly what you want, while
providing a name for the inner function.
Regards
NH
reddaly wrote:
>
> On Jul 28, 3:09 pm, johnjbarton <[email protected]> wrote:
>
>> On Jul 28, 2:23 pm, reddaly <[email protected]> wrote:
>> ...
>>
>>
>>>> Nevertheless I am interested in any incremental suggestions about
>>>> function names.
>>>>
>>> My suggestion is to inspect the function object for an explicit, user-
>>> defined name.
>>>
>> I've heard this suggestion before, I didn't understand it. If you
>> don't want anonymous functions, why don't you just name them? I mean
>> aren't function names are exactly equal to explicit user-defined
>> names?
>>
>
> You suggest using a form like
>
> function myName() { ...}
>
> instead of
>
> var x = function () { ...}
>
> x.firebugName = "myName"
>
> However, this does not always work out. Consider the case where a
> function returns another function.
>
> function compose (fn1, fn2) {
> // returns a function that calls fn1 with the result of fn2
> return function() { return fn1( fn2.apply(null, arguments)) }
> }
>
> Here, there is no sensible way to name the composed function (other
> than "composed function," which does not give any context about the
> functions it comprises). Ideally, you would like to name it something
> recognizable. e.g. compose(tagName, firstTag) would be named
> "tagName_firstTag." The way to accomplish this best is to set a
> property on the function that firebug will inspect.
>
> Best regards,
> Red
>
>
>> jjb
>>
> >
>
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