I have just tried to debug code where a variable returned by a function remaind undefined when i simply step over it. But if I choose to dig into the function and passes over all steps in the function, the variable is initialized with the desired result.
Is this known/intenden behaviour? I admit that I am new to JavaScript and thus javascript debugging, so maybe I am missing something TIA /Soeren -- You received this message because you are subscribed to the Google Groups "Firebug" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at https://groups.google.com/forum/#!forum/firebug
