URLs and other web stuff may be encoded using '%' signs. so "%2e" is '.',
"%77" is 'w', thus "%77%77%77" is "www". you can even mix things, so
"%77w%77" is also "www".
to decode the stuff, you can use perl functions generally found in
CGI-scripting module/libs.
search for URLdecode or something like that, then to decode a "cryptic" url,
replace '@' by '\@'
(cos' perl no more accepts unescaped '@' in strings) and print the result of
URLdecode($string).
you can certainly do that in other languages, but perl is just that handy...
(what? no perl on the firewall? you're kidding? why not a firewall without a
kernel. that would be
really secure, no? ;-}).
note that you can let your browser do part (or all) of the work for you:
just click on the url and see which site it is contacting. however, this is
not the safest method...
> -----Original Message-----
> From: Micheal Espinola Jr [mailto:[EMAIL PROTECTED]]
> Sent: Wednesday, March 15, 2000 7:14 PM
> To: mouss; [EMAIL PROTECTED]
> Subject: RE: Speaking of blocking porn...
>
>
> What are you (or others on this list) using to reformat cryptic
> IP addresses
> such as these? Is there a program to automate this, or is there a
> mathematical formula?
>
> | -----Original Message-----
> | From: [EMAIL PROTECTED]
> | [mailto:[EMAIL PROTECTED]]On Behalf Of mouss
> | Sent: Wednesday, March 15, 2000 8:37 AM
> | To: [EMAIL PROTECTED]
> | Subject: Re: Speaking of blocking porn...
> |
> | actually it matches the format http://user:password@ipaddress
> | where ip address is 374393, which in quad-dots is 0.5.182.121 (because
> | 121+256*182+256*256*5 = 374393. however, 0.5.182.121 is a "reserved"
> | address.
> | so you should get nothing by trying to get the URL above.
>
>
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