[This message was posted by Rolf Andersson of Pantor Engineering 
<[email protected]> to the "FAST Protocol" discussion forum at 
http://fixprotocol.org/discuss/46. You can reply to it on-line at 
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> Rolf,
> 
> I am sorry I got confused again. For tag 271, the pmap bit is 0.
> so the default value 0 is used for exponent. Can we say that the
> exponent has a value so that we need to decode mantissa?
> If so, the encoded value is 0x82 for the mantissa. The decoded
> value should be 1 since it is delta operator, Right?

Yes, 0x82 is for the mantissa.
No, the decoded mantissa value is 2.
Why do you think the value should be 1?

> BTW, if the length field of a sequence field is greater than 1,
> does the sequence pmap appear each iteration?

yes, as noted in my mail below

(FAST 1.1 spec section 6.2.5 says: "If any instruction of the group needs to 
allocate a bit in a presence map, each element is represented as a segment in 
the transfer encoding." "element" in this context is synonymous with my use of 
"iteration" in my mail below)

/Rolf

... snip ...

>> Michael,
>>
>> The pmap entry for the length field is located in the _message_
>> level pmap (bit 7 in this case). The sequence level pmap occurs
>> for every iteration (repetition) of the sequence and provides
>> presence info for the fields in the current iteration.


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