[This message was posted by Michael Wong of Chi-X Global Technology 
<[email protected]> to the "FAST Protocol" discussion forum at 
http://fixprotocol.org/discuss/46. You can reply to it on-line at 
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Rolf,

First, since the length field has an operator, does it occupy the first bit of 
sequence PMAP? if so, I would like to know why pmap bit 5 is for 271.

For 271, exponent=0(not -2) (copy not default) mantissa=2 => 2*10^0 = 2
it is correct if I decode it in such way. However, the operator of exponent is 
copy , not default. In this situation, PMAP bit is 0 and it is optional, that 
means the exp. is absent, right?

BTW, this is the output for the first msg provided by swx
8=FIXT.1.1 35=X 1128=7 49=SWXGROUP-MDI.M01 56=SWXGROUP-MDC 34=10576 97=N 
52=20080623-03:55:01.799 1021=1 268=1 279=0 269=0 48=CH0003671440 22=4 271=2 
273=03:45:00.003 336=ABQ5 346=1 6566=0 83=1 

Michael

> Michael,
> 
> your decoding up to 270 looks alright if I have understood the context
> correctly.
> 
> For 271 (field 5 in the sequence), pmap bit 5 is 0 so the wire
> representation 0x82 corresponds to: exponent=-2 (default) mantissa=2
> => 2*10^-2?
> 
> 270=NULL followed by 271=2*10^-2 don't make much sense though?
> 
> I suggest you contact SWX for assistance on this. Let us know
> what they say.
> 
> Best, Rolf
> 
> > Rolf,
> >
> > The previous message can be decoded successfully after you told me the
> > sequence field PMAP. However, I have another messege that I fail to
> > decode it
> >
> > msg (block size field is omitted):
> >
> > F7 01 C8 53 57 58 47 52 4F 55 50 2D 4D 44 49 2E 4D 30 B1 52 D0 32 30
> > 30 38 30 36 32 33 2D 30 33 3A 35 35 3A 30 31 2E 37 39 B9 81 81 1B B0
> > 43 48 30 30 30 33 36 37 31 34 34 B0 80 82 30 33 3A 34 35 3A 30 30 2E
> > 30 30 B3 41 42 51 B5 81 FF 80 80 40 B0 02 AC 32 30 30 38 30 36 32 33
> > 2D 30 33 3A 34 35 3A 30 30 2E 30 30 B3 82 C5 01 C8 38 30 B0 82 14 88
> > 39 37 37 31 39 B3 82 80 81 81 81 A0 B1 FF 81 81 C0 02 AC C1 01 C8 81
> > 34 88 B0 36 32 32 37 36 31 B2 81 98 81 81 81 C0 02 AC C0 01 C8 14 88
> > 37 31 38 36 39 38 B1 82 E8 81 81 81 C0 02 AC C5 01 C8 B1 82 18 88 31
> > 30 35 37 30 37 35 B9 81 03 CB AF 81 81 81 A0 B1 A0 A5 81 81 81 81 18
> > 88 4C 49 30 30 31 30 37 33 37 32 31 B6 82 7C B0 C4 81 81 81 85 B4 82
> > 38 88 B0 43 48 30 30 30 39 36 39 31 36 30 B8 80 EB 84 81 81 A4 B1 81
> > FF FD 81 C0 02 AC C0 01 C8 3C 88 B0 31 31 31 37 38 32 35 B5 81 00 F7
> > 82 00 C8 81 81 81 A0 B1 8D 01 B4 81 81 81 81 3C 88 B0 36 39 33 36 30
> > B0 82 7E FB 81 7E 82 81 81 81 80 18 88 34 38 34 30 36 B7 80 81 81 81
> > 81 C0 02 AC C0 01 C8 14 88 32 33 33 37 34 32 B1 83 FF 81 81 81 C0 02
> > AC C0 01 C8 3C 88 B1 35 35 34 B0 81 93 82 00 FC 81 81 81 80 3C 88 B0
> > 35 38 33 34 30 B4 80 84 7F BB 82 81 81 C0 02 AC C0 01 C8 1C 88 32 37
> > 31 36 38 B7 82 FC 83 CA FF
> >
> > PMAP = F7 (1 1110111) TID = 01 C8 49 = 53 57 58 47 52 4F 55 50 2D 4D
> > 44 49 2E 4D 30 B1 34 = 52 D0 52 = 32 30 30 38 30 36 32 33 2D 30 33 3A
> > 35 35 3A 30 31 2E 37 39 B9 1021 = 81 268 = 81 Seq PMAP = 1B B0
> > (0011011 1 0110000) 48 = 43 48 30 30 30 33 36 37 31 34 34 B0 270 = 80
> > 271 = 82 ?
> >
> > I don't know how to proceed after tag 270. Template
> > http://www.2shared.com/file/5736462/b9436b42/template1.html
> >
> > Thanks Michael
> > > Michael,
> > >
> > > the length field occupies a bit in the message pmap if there is an
> > > operator specified for the length field of the sequence.
> > >
> > > I don't have the FAST spec in front of me but IIRC section 6.2.5
> > > contains info about sequences.
> > >
> > > I can check more closely if you send me the template you are using.
> > >
> > > /Rolf
> > >
> > > > Rolf,
> > > >
> > > > I want to know if the first bit of PMAP for sequence field
> > > > indicate the presence of length field or not. Is there related
> > > > information in the spec?
> > > >
> > > > Thanks Michael


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