*UNTESTED*, but this was my thought...
var level:int = 5;
var xmlItem:* = xml.menu;
for (var i:int = 0; i < level; i++) {
xmlItem = xmlItem.item[this["whichItem" + ((i == 0) ? "" : i)]];
}
totalItems = xmlItem.item.length;
I am doing this: ["whichItem" + ((i == 0) ? "" : i)]
because I have no idea where that value comes from or what its for...
On Thu, Aug 11, 2011 at 11:48 AM, Merrill, Jason <
[email protected]> wrote:
> You just need a recursive loop to do this. So I would write a function
> that handles each node level individually, adding to a class-level private
> property called something like, _totalItems. The function basically checks
> the XML node to see if it has any children. If it does, it calls itself,
> passing in the child XML node as an argument, and does the count the node,
> adding to the _totalItems private class property. The function then does
> not call itself again if the XML node does not have any children. No switch
> statement would be needed. Make sense?
>
>
> Jason Merrill
> Instructional Technology Architect II
> Bank of America Global Learning
>
>
>
>
>
> _______________________
>
> -----Original Message-----
> From: [email protected] [mailto:
> [email protected]] On Behalf Of John Polk
> Sent: Thursday, August 11, 2011 11:31 AM
> To: Flash List
> Subject: [Flashcoders] Simplify XML Call
>
> Hi;
> I have this code:
>
> switch (level)
> {
> case 2:
> totalItems = xml.menu.item[whichItem].item.length();
> break;
> case 3:
> totalItems =
> xml.menu.item[whichItem].item[whichItem2].item.length();
> break;
> case 4:
> totalItems =
> xml.menu.item[whichItem].item[whichItem2].item[whichItem3].item.length();
> break;
> case 5:
> totalItems =
> xml.menu.item[whichItem].item[whichItem2].item[whichItem3].item[whichItem4].item.length();
> break;
> }
>
>
>
> Ugly, I know. How do I write one or two lines that does all that and even
> better: loops it?
> TIA,
> John
>
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