sorry should have been this:
var level:int = 5;
var xmlItem:* = xml.menu;
for (var i:int = 1; i < level; i++) {
xmlItem = xmlItem.item[this["whichItem" + ((i == 1) ? "" : i)]];
}
totalItems = xmlItem.item.length;
On Thu, Aug 11, 2011 at 11:54 AM, Ktu <[email protected]>wrote:
> *UNTESTED*, but this was my thought...
>
> var level:int = 5;
>
> var xmlItem:* = xml.menu;
> for (var i:int = 0; i < level; i++) {
> xmlItem = xmlItem.item[this["whichItem" + ((i == 0) ? "" : i)]];
> }
> totalItems = xmlItem.item.length;
>
>
>
> I am doing this: ["whichItem" + ((i == 0) ? "" : i)]
> because I have no idea where that value comes from or what its for...
>
>
>
>
>
>
> On Thu, Aug 11, 2011 at 11:48 AM, Merrill, Jason <
> [email protected]> wrote:
>
>> You just need a recursive loop to do this. So I would write a function
>> that handles each node level individually, adding to a class-level private
>> property called something like, _totalItems. The function basically checks
>> the XML node to see if it has any children. If it does, it calls itself,
>> passing in the child XML node as an argument, and does the count the node,
>> adding to the _totalItems private class property. The function then does
>> not call itself again if the XML node does not have any children. No switch
>> statement would be needed. Make sense?
>>
>>
>> Jason Merrill
>> Instructional Technology Architect II
>> Bank of America Global Learning
>>
>>
>>
>>
>>
>> _______________________
>>
>> -----Original Message-----
>> From: [email protected] [mailto:
>> [email protected]] On Behalf Of John Polk
>> Sent: Thursday, August 11, 2011 11:31 AM
>> To: Flash List
>> Subject: [Flashcoders] Simplify XML Call
>>
>> Hi;
>> I have this code:
>>
>> switch (level)
>> {
>> case 2:
>> totalItems = xml.menu.item[whichItem].item.length();
>> break;
>> case 3:
>> totalItems =
>> xml.menu.item[whichItem].item[whichItem2].item.length();
>> break;
>> case 4:
>> totalItems =
>> xml.menu.item[whichItem].item[whichItem2].item[whichItem3].item.length();
>> break;
>> case 5:
>> totalItems =
>> xml.menu.item[whichItem].item[whichItem2].item[whichItem3].item[whichItem4].item.length();
>> break;
>> }
>>
>>
>>
>> Ugly, I know. How do I write one or two lines that does all that and even
>> better: loops it?
>> TIA,
>> John
>>
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>
>
> --
> Ktu;
>
> The information contained in this message may or may not be privileged
> and/or confidential. If you are NOT the intended recipient, congratulations,
> you got mail!
>
--
Ktu;
The information contained in this message may or may not be privileged
and/or confidential. If you are NOT the intended recipient, congratulations,
you got mail!
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