string = XPath.selectNodes(my_xml, "/path/to/nodes").nodeValue;
This results in undefined.
Johannes Nel wrote:
try dropping the last slash in ur xpath statement
On 12/7/05, Merrill, Jason <[EMAIL PROTECTED]> wrote:
Why is it a workaround? Doesn't the XPath return the XMLNode?
I haven't used this XPath-extension, but maybe I should check i out.
Morten, I'm not sure it returns the actual node - it might convert it to
another object instead because I too cannot get your suggestions to
work. Could you send an xfactorstudio Xpath Actionscript example of
what you mean? If you haven't used those classes before, then its
interesting that you are giving advice about a product you don't seem to
know the details of. I like Mike cannot get your suggestions to work,
which if I am interpreting correctly, would mean:
myString =
XPath.selectNodes(my_xml,"rootNode/myChildNodeNode/myChildNode/").nodeVa
lue;
That returns undefined when I try it. Or are you suggesting something
else?
Jason Merrill | E-Learning Solutions | icfconsulting.com
NOTICE:
This message is for the designated recipient only and may contain
privileged or confidential information. If you have received it in error,
please notify the sender immediately and delete the original. Any other use
of this e-mail by you is prohibited.
_______________________________________________
Flashcoders mailing list
Flashcoders@chattyfig.figleaf.com
http://chattyfig.figleaf.com/mailman/listinfo/flashcoders
--
j:pn
_______________________________________________
Flashcoders mailing list
Flashcoders@chattyfig.figleaf.com
http://chattyfig.figleaf.com/mailman/listinfo/flashcoders
_______________________________________________
Flashcoders mailing list
Flashcoders@chattyfig.figleaf.com
http://chattyfig.figleaf.com/mailman/listinfo/flashcoders
