This will give you what you're looking for:
var cols:Number = 3;
var rows:Number = 3;
for(var i:Number=0;i<rows;i++)
{
for(var j:Number=0;j<cols;j++)
{
var gridLocation:Number = (i+j) + ((rows-1)*i);
trace("grid location = " + gridLocation);
// create your moviecilp
}
}
row by row, create a movieclip per column.
hth,
John
On 3/29/06, Flash Mel <[EMAIL PROTECTED]> wrote:
>
> Ok, since my email got through this morning, I'm hoping this one gets
> through. Here is the question I've emailed four times now. Doesn't
> show up in the threads.
>
> Here we go:
>
>
>
> Here is what I have so far:
>
> import mx.transitions.Tween;
> import mx.transitions.easing.*;
>
> m = 0;
> numTiles = 112;
>
> function placeTiles() {
> if (m == numTiles){
> m = 0;
> clearInterval(buildTiles);
> } else {
> _root.attachMovie("square", "tile" + m + "_mc", m, {_x:m % 14
> * 50, _y:Math.floor(m / 14) * 50});
> myObj = "tile" + m + "_mc";
> new Tween(_root[myObj], "_alpha", Regular.easeInOut, 0, 100, 35,
> false);
> _root[myObj].number_text.text = m;
> m++;
> }
> }
>
> buildTiles = setInterval(placeTiles, 30);
>
> This works fine. Builds the rows one after another. But what I am
> trying to do is build one row across and one down. Make sense?
>
> In essence, the final display and position of the objects will be:
>
> 123
> 456
> 789
>
> The sequence I am after:
>
> 1
>
> then
>
> 12
> 4
>
> then
>
> 123
> 45
> 7
>
> and so on
>
> 123
> 456
> 78
>
> Help?!
> _______________________________________________
> Flashcoders@chattyfig.figleaf.com
> To change your subscription options or search the archive:
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>
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--
John Grden - Blitz
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