When you trace out:
trace(staff.*.(POSITION == "Designer"));
You will see that it returns the parent <EMPLOYEE> element... So, even
if your code were to work, all it would do would be to return the root
<STAFF> node, which probably wouldn't help you.
If you compare the two examples, you will see that there is only one
<POSITION> node within each <EMPLOYEE> node...
If you modify the staff XML to be:
var staff:XML = <STAFF>
<EMPLOYEE ID="501" HIRED= "1090728000000">
<NAME>Marco Crawley</NAME>
<MANAGER>James Crawley</MANAGER>
<POSITION>Designer</POSITION>
<POSITION>Programmer</POSITION>
</EMPLOYEE>
</staff>
It will no longer work.
Also, you should be using attributes as opposed to entering values
directly into nodes. I personally never filter e4x through the node
value, but rather through attribute values, like so...
var staff2:XML=<STAFF>
<EMPLOYEE name="fred">fred</EMPLOYEE>
<EMPLOYEE name="bob">bob</EMPLOYEE>
<EMPLOYEE name="leroy">leroy</EMPLOYEE>
<EMPLOYEE name="algernon">algernon</EMPLOYEE>
</STAFF>
trace("find leroy: " +staff2.*.(@name=="leroy").toXMLString());
Hope this helps.
- Taka
On Thu, Feb 19, 2009 at 5:22 PM, Ferd Berfel <[email protected]> wrote:
> hello, newbie here...
>
>
> I'm trying to understand searching xml with e4x
>
> why does this work:
>
> var staff:XML = <STAFF>
> <EMPLOYEE ID="501" HIRED= "1090728000000">
> <NAME>Marco Crawley</NAME>
> <MANAGER>James Crawley</MANAGER>
> <POSITION>Designer</POSITION>
> </EMPLOYEE>
> </staff>
>
> var results:XMLList= staff.*.(POSITION == "Designer")
>
> and this does not?
>
> var staff2:XML=<STAFF>
> <EMPLOYEE>fred</EMPLOYEE>
> <EMPLOYEE>bob</EMPLOYEE>
> <EMPLOYEE>leroy</EMPLOYEE>
> <EMPLOYEE>algernon</EMPLOYEE>
> </STAFF>
>
> trace("find leroy: " +staff2.(EMPLOYEE=="leroy"));
>
> but more importantly, how WOULD I find leroy? (I know I can create a
> function to loop through children, but I'm wondering how to do it within the
> format describe)
>
>
> tia
> ferd
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