If you want to find the EMPLOYEE node you can do something like:
trace(staff2.EMPLOYEE.(text()[0] == "leroy").toXMLString());
trace(staff2.EMPLOYEE.(child(0) == "leroy").toXMLString());
trace(staff2.EMPLOYEE.(toString() == "leroy").toXMLString());
Kenneth Kawamoto
http://www.materiaprima.co.uk/
Ferd Berfel wrote:
hello, newbie here...
I'm trying to understand searching xml with e4x
why does this work:
var staff:XML = <STAFF>
<EMPLOYEE ID="501" HIRED= "1090728000000">
<NAME>Marco Crawley</NAME>
<MANAGER>James Crawley</MANAGER>
<POSITION>Designer</POSITION>
</EMPLOYEE>
</staff>
var results:XMLList= staff.*.(POSITION == "Designer")
and this does not?
var staff2:XML=<STAFF>
<EMPLOYEE>fred</EMPLOYEE>
<EMPLOYEE>bob</EMPLOYEE>
<EMPLOYEE>leroy</EMPLOYEE>
<EMPLOYEE>algernon</EMPLOYEE>
</STAFF>
trace("find leroy: " +staff2.(EMPLOYEE=="leroy"));
but more importantly, how WOULD I find leroy? (I know I can create a
function to loop through children, but I'm wondering how to do it within the
format describe)
tia
ferd
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