Hi,

isn't the absence of break statements messing things up?

greetz
JC

On Thu, Apr 2, 2009 at 12:08 PM, Jiri <[email protected]> wrote:

> I am new to bitwise operators, so I am trying to learn it.
>
> I have the following code and it works half. I am using a switch case to
> get the result, but this is messing things up. I could revert to and if -
> else statement, but I was wondering if there is a more elagant way of doing
> it. I post my code below, and would have some advice.
>
> var NO_RESTRICTION:int = 1;
> var NUM_ONLY:int = 2;
> var CHAR_ONLY:int = 4;
>
> var RESTRICTION:int =  NUM_ONLY ;
>
> function setInputCharRestriction(tInt:int):void {
>        RESTRICTION = tInt | tInt&2 | tInt&3;
> }
>
> function getRestrict():String{
>                var tRestrict:String = '';
>
>                trace('all ' , Boolean(RESTRICTION&1))
>                trace('num ' , Boolean(RESTRICTION&2))
>                trace('char ' ,Boolean(RESTRICTION&4))
>
>                switch(RESTRICTION){
>                        case RESTRICTION&1 :
>                                tRestrict +="\u0020-\u007E";
>                                trace('all')
>                        case RESTRICTION&2:
>                                tRestrict =" 0-9";
>                                trace('num')
>                        case RESTRICTION&4:
>                                tRestrict =" A-Z a-z";
>                                trace('char')
>                }
>                trace('restrict field ' , tRestrict)
>                return tRestrict;
> }
>
> getRestrict()
>
> Thank you.
>
> Jiri
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