On 16/10/2011 13:01, Paul Andrews wrote:
On 16/10/2011 10:06, Kenneth Kawamoto wrote:
Here's one way:
var xml:XML = <my_xml>
<row id="a" parent="a" />
<row id="b" parent="a" />
<row id="c" parent="a" />
<row id="d" parent="d" />
<row id="e" parent="d" />
<row id="f" parent="d" />
</my_xml>;
var ids:Array = ["a", "d"];
for each (var s:String in ids){
xml.row.(@id == s).children = xml.row.(@parent == s && @id != s);
while(xml.row.(@parent == s && @id != s).length()) delete
xml.row.(@parent == s && @id != s)[0];
}
trace(xml);
Thanks Kenneth. That works very nicely. I appreciate you taking the
time to do my little puzzle!
I made one change:
for each (var s:String in xml.row.(@id == @parent).@id){
xml.row.(@id == s).children = xml.row.(@parent == s && @id != s);
while(xml.row.(@parent == s && @id != s).length()) delete
xml.row.(@parent == s && @id != s)[0];
}
Thank you!
Ah, I went one stage further, which breaks the necessity for the parent
to have @id == @parent:
var xml:XML = <my_xml>
<row id="a" parent="a" />
<row id="b" parent="a" />
<row id="c" parent="a" />
<row id="d" parent="d" />
<row id="e" parent="d" />
<row id="f" parent="d" />
<row id="g" parent="e" />
<row id="h" parent="e" />
<row id="i" parent="h" />
</my_xml>;
Scratching my head again.. !
Paul
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