How do I pad the bootloader. img to 8MBytes ? But, still it occupies the first 106976 Bytes right ? Remaining space is empty I suppose.
Thanks. On Aug 1, 2016 9:08 PM, "Urja Rannikko" <urja...@gmail.com> wrote: > Hi, > > On Mon, Aug 1, 2016 at 10:33 AM, Pradeep Ch <shanm...@sysargus.com> wrote: > > > > I am attempting to write to a flashrom using layout/region approach. > > The NOR flash size is 8MBytes. The file size I am writing is 106976 > Bytes. > > > > The rom.layout file contents are: > > 00000000:0001a1df test1 > > 0001a1e0:007fffff test2 > > > > The command I am using is: > > ./flashrom -p ft2232_spi:type=arm-usb-ocd --layout rom.layout --image > test1 > > -w bootloader.img > > > > The error I am getting is : > > Using region: "test1". > > Calibrating delay loop... OK. > > Found Eon flash chip "EN25Q64" (8192 kB, SPI) on ft2232_spi. > > Error: Image size (106976 B) doesn't match the flash chip's size (8388608 > > B)! > > > > Please let me know about the error. > > The current layout system will only limit the actually written area, > not change the requirements of the flash file being the size of the > chip, so in this case you'd need to pad the bootloader.img to 8MB. >
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