On Mon, Aug 1, 2016 at 9:59 AM, Pradeep Ch <shanm...@sysargus.com> wrote:
> How do I pad the bootloader. img to 8MBytes ? But, still it occupies the > first 106976 Bytes right ? Remaining space is empty I suppose. > To create a 8MB file full of 0xff bytes: dd if=/dev/zero bs=1k count=8192 2>/dev/null | tr "\000" "\377" > test.bin >From there, you can use dd with skip=, seek=, and conv=notrunc to place your content wherever you need to in the image. For example, dd if=test1.bin of=test.bin bs=1 conv=notrunc dd if=test2.bin of=test.bin bs=1 seek=$((0x1a1e0)) conv=notrunc Thanks. > On Aug 1, 2016 9:08 PM, "Urja Rannikko" <urja...@gmail.com> wrote: > >> Hi, >> >> On Mon, Aug 1, 2016 at 10:33 AM, Pradeep Ch <shanm...@sysargus.com> >> wrote: >> > >> > I am attempting to write to a flashrom using layout/region approach. >> > The NOR flash size is 8MBytes. The file size I am writing is 106976 >> Bytes. >> > >> > The rom.layout file contents are: >> > 00000000:0001a1df test1 >> > 0001a1e0:007fffff test2 >> > >> > The command I am using is: >> > ./flashrom -p ft2232_spi:type=arm-usb-ocd --layout rom.layout --image >> test1 >> > -w bootloader.img >> > >> > The error I am getting is : >> > Using region: "test1". >> > Calibrating delay loop... OK. >> > Found Eon flash chip "EN25Q64" (8192 kB, SPI) on ft2232_spi. >> > Error: Image size (106976 B) doesn't match the flash chip's size >> (8388608 >> > B)! >> > >> > Please let me know about the error. >> >> The current layout system will only limit the actually written area, >> not change the requirements of the flash file being the size of the >> chip, so in this case you'd need to pad the bootloader.img to 8MB. >> > > _______________________________________________ > flashrom mailing list > flashrom@flashrom.org > https://www.flashrom.org/mailman/listinfo/flashrom > -- David Hendricks (dhendrix) Systems Software Engineer, Google Inc.
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