FWIW, if you are worried about performance, I would test the efficiency of
using a map, especially if age is an int and not a Number. Even if it is a
Number I might still test out a map with a Math.floor on the age.
Var agemap:Object {
0 : 1, 1: 1, 2: 1, 3: 2, 4: 2, 5: 2, 6: 3, 7: 3, 8: 3... 19: 6 }
Function get AgeGroup(age:Number):int
{
var intAge:int = Math.floor(age); // if needed
return int(ageMap[intAge);
}
On 4/9/10 9:03 PM, "Joe Cabezas" <[email protected]> wrote:
y did not understand, but i hope i help you
2010/4/9 Wally Kolcz <[email protected]>
Thanks for the try, but all ages are > 18 so the first condition would be met
on all of them. I need the multiple conditions on the case to be preserved. :)
On 4/9/2010 11:45 PM, Rob Romanek wrote:
This is off the top of my head in email so there may be some errors but
something like this should work
var category:Number;
switch (true){
case(age > 18):
category = 0;
break;
case(age > 15):
category = 6;
break;
case(age > 12):
category = 5;
break;
case(age > 8):
category = 4;
break;
case(age > 5):
category = 3;
break;
case(age > 2):
category = 2;
break;
default:
category = 1;
}
return category;
hth,
Rob
On 9-Apr-10, at 10:45 PM, Wally Kolcz wrote:
Can someone rewrite this as a switch/case? I tried, but it didn't seem
to work. Problem I am running into is the multiple conditions in the
case. Thanks!
private function getAgeGroup(birthday:Date):int {
var age:int = getAge(birthday);
if (age >= 0 && age >3){ //Birth to 2
return 1;
}else if (age >=3 && age >6){ //3 to 5
return 2;
}else if (age >=6 && age >9){ //6 to 8
return 3;
}else if (age >=9 && age >13){ //9 to 12
return 4;
}else if (age >=13 && age >16){ //13 to 15
return 5;
}else if (age >=16 && age >19){ //16 to 18
return 6;
}else { //Older or Adults
return 0;
}
}
--
Alex Harui
Flex SDK Team
Adobe System, Inc.
http://blogs.adobe.com/aharui
