You didn't say what error you're getting when you compare with null (?)

On 4/23/07, [EMAIL PROTECTED] <[EMAIL PROTECTED]> wrote:
> I have a class, "Player" that with a "selectPlayer" method.
> I want "selectPlayer" to automatically deselect the last selected Player
> that stored in
> the static variable "LAST_SELECTED".
>
> It's imperative that I keep LAST_SELECTED data type as "Player".
> I don't want give it the dynamic datatype.
>
> What's a more elegant way to test if LAST_SELECTED is defined without
> getting an Error?
>
>
>
> Normally in AS2, I would just declare it null in class variables and
> later define it when selectPlayer is called like:
>
> function selectPlayer()
> {
>   if(Player.LAST_SELECTED == null){
>      Player.LAST_SELECTED = this;
>   }
> }
>
> But the testing of "null" causes an Error when a variable's datatype is set.
> So I can't use this lazy AS2 tactic anymore. ;)
>
> [CODE]
>
> import mx.core.UIComponent;
> import mx.controls.Alert;
>
> class Player extends UIComponent
> {
>    private static var LAST_SELECTED:Player
>
>    public function Player():void
>    {
>      /*****
>      Whenever I create a new Player defining LAST_SELECTED here fixes
> the Error
>      But I purposely don't want each new created Player to be set as
> LAST_SELECTED.
>      ******/
>      //I don't want this so I comment it out.
>      //--->Player.LAST_SELECTED=new Player();
>    }
>
>    private function selectPlayer():void
>    {
>       try
>         {
>          if(Player.LAST_SELECTED != this){
>             //Restore the last selected Player to normal scale.
>             Player.LAST_SELECTED.scaleX=100;
>             Player.LAST_SELECTED.scaleY=100;
>
>             //Assign this current Instance as the LAST_SELECTED Player.
>             Player.LAST_SELECTED=this;
>
>             //Set the scale to show the new selected instance .
>             scaleX=150;
>             scaleY=150;
>          }
>       }catch(e:Error){
>          Alert.show(e.message,e.name);
>       }
>    }
>
> }
>
> [/CODE]
>
>
> Thanks for your time,
> --Keith H--
>
>
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