Re: [flexcoders] Array Item Counting

[Paul Andrews]

----- Original Message ----- 
From: "Paul Andrews" <[EMAIL PROTECTED]>
To: <flexcoders@yahoogroups.com>
Sent: Wednesday, January 23, 2008 10:47 PM
Subject: Re: [flexcoders] Array Item Counting


> ----- Original Message ----- 
> From: "jmfillman" <[EMAIL PROTECTED]>
> To: <flexcoders@yahoogroups.com>
> Sent: Wednesday, January 23, 2008 10:25 PM
> Subject: [flexcoders] Array Item Counting
> 
> 
>>I have an array with several dynamically populated numbers. The array 
>> is then sorted to group identical values together.
>> 
>> Let's say my array contains the following:[15,15,35,35,35,35, 
>> 35,55,55,75,95,105,115,115,115]
>> 
>> What I need to do is get a count of each number, and determine the 
>> highest frequency, in the above example, the number 35 is listed 4 
>> times, so I would need to set a variable = 4. I've been playing around 
>> with a for loop. Since I have 168 potential matches (15, 35, 55, 75, 
>> 95, all the way to 2875) incrementing by 20, that's a bit excessive for 
>> a bunch of if statements. It seems like a nested for loop could do 
>> this, but I can't figure it out. Maybe there's an even better way I 
>> haven't considered.
>> 
>> for (var rowCount:int=0;rowCount < arrayRows.length;rowCount++){
>>     var my15:int;
>>     if (arrayRows[rowCount].row == 15){
>> my15 = my15+1;
>> trace (my15);
>>     }
>> }
> 
> var myArr:Array = [15,15,35,35,35,35,35,55,55,75,95,105,115,115,115];
> var longest:Number=0;
> var curRun:Number=1;
> var curr:Number;
> var prev:Number = myArr[0]-1;
> 
> for (var idx:Number=0; idx<myArr.length; idx++){
>    curr = myArr[idx];
>     if (curr == prev) {
>          curRun++;
>     } else {
>          if (curRun > longest) {
>               longest = curRun;
>          }
>      curRun =1;
>      prev=curr;
>     }
> }
> trace(longest);

LOL it's late:

var myArr:Array = [15,15,35,35,35,35,35,55,55,75,95,105,115,115,115];
var longest:Number=1;
var curRun:Number=1;
var curr:Number;
var prev:Number = myArr[0];

for (var idx:Number=1; idx<myArr.length; idx++){
    curr = myArr[idx];
     if (curr == prev) {
          curRun++;
          if (curRun > longest) {
               longest = curRun;
          }
     } else {
      curRun =1;
      prev=curr;
     }
}
trace(longest);