Not to be harsh, but this sounds like something my first cs course in
college would have had as an assignment or problem in a homework set.
This has nothing to do with flex.
var A:Array = [15,15,35,35,35,35, 35,55,55,75,95,105,115,115,115];
var B:Array = new Array();
Var maxrun:Number=0;
for each(var n:Number in A)
{
if(!B[n]) B[n]=1;
else B[n]++;
if(B[n]>maxrun) maxrun=B[n];
}
From: flexcoders@yahoogroups.com [mailto:[EMAIL PROTECTED] On
Behalf Of jmfillman
Sent: Wednesday, January 23, 2008 2:26 PM
To: flexcoders@yahoogroups.com
Subject: [flexcoders] Array Item Counting
I have an array with several dynamically populated numbers. The array
is then sorted to group identical values together.
Let's say my array contains the following:[15,15,35,35,35,35,
35,55,55,75,95,105,115,115,115]
What I need to do is get a count of each number, and determine the
highest frequency, in the above example, the number 35 is listed 4
times, so I would need to set a variable = 4. I've been playing around
with a for loop. Since I have 168 potential matches (15, 35, 55, 75,
95, all the way to 2875) incrementing by 20, that's a bit excessive for
a bunch of if statements. It seems like a nested for loop could do
this, but I can't figure it out. Maybe there's an even better way I
haven't considered.
for (var rowCount:int=0;rowCount < arrayRows.length;rowCount++){
var my15:int;
if (arrayRows[rowCount].row == 15){
my15 = my15+1;
trace (my15);
}
}
