I doubt it's possible. Having two visible doesn't really fit with the idea
of a stack.
Why not roll your own component?
Paul
----- Original Message -----
From: "m.frigge" <[EMAIL PROTECTED]>
To: <flexcoders@yahoogroups.com>
Sent: Tuesday, February 19, 2008 5:40 PM
Subject: [flexcoders] Re: Is it possible to have 2 children of viewstack
visible?
> Knock.. knock.. nobody knows this??
> A simple no it doesn't work would be alright too :-) ???
>
>
> --- In flexcoders@yahoogroups.com, Max Frigge <[EMAIL PROTECTED]> wrote:
>>
>> Hi,
>>
>> I am trying to create a slide effect for a ViewStack. Therefor
>> I would need to have 2 children visible at the same time, so that
>> you can see the second child sliding in while the first one is
>> sliding out. Is that possible or am I on the wrong path?
>>
>> I want something like this:
>>
>> <?xml version="1.0"?>
>> <!-- containers\navigators\VSLinkEffects.mxml -->
>>
>>
>> <mx:Parallel id="toSecond">
>> <mx:Move duration="400" xFrom="{search.x}"
> xTo="{search.width}" target="{search}"/>
>> <mx:Move duration="400" xFrom="{-custInfo.width}"
> xTo="{custInfo.x}" target="{custInfo}"/>
>> </mx:Parallel>
>>
>> <mx:ViewStack id="myViewStack"
>> borderStyle="solid"
>> width="200"
>> creationPolicy="all">
>>
>> <mx:Canvas id="search"
>> label="Search" >
>> <mx:Label text="Search Screen"/>
>> </mx:Canvas>
>>
>> <mx:Canvas id="custInfo"
>> label="Customer Info">
>> <mx:Label text="Customer Info"/>
>> </mx:Canvas>
>> </mx:ViewStack>
>>
>> <mx:Button click="toSecond.play()" label="Play Effect" />
>> </mx:Application>
>>
>>
>>
>>
>>
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