Max,

I would think that States with transition effects would be the 
easiest way to do this.

Jason
--- In [email protected], "m.frigge" <[EMAIL PROTECTED]> wrote:
>
> Knock.. knock.. nobody knows this?? 
> A simple no it doesn't work would be alright too :-) ???
> 
> 
> --- In [email protected], Max Frigge <m.frigge@> wrote:
> >
> > Hi,
> > 
> > I am trying to create a slide effect for a ViewStack. Therefor 
> > I would need to have 2 children visible at the same time, so that
> > you can see the second child sliding in while the first one is
> > sliding out. Is that possible or am I on the wrong path?
> > 
> > I want something like this:
> > 
> > <?xml version="1.0"?>
> > <!-- containers\navigators\VSLinkEffects.mxml -->
> > 
> >     
> >     <mx:Parallel id="toSecond">
> >         <mx:Move duration="400" xFrom="{search.x}"
> xTo="{search.width}" target="{search}"/>
> >         <mx:Move duration="400" xFrom="{-custInfo.width}"
> xTo="{custInfo.x}" target="{custInfo}"/>
> >     </mx:Parallel>
> >      
> >     <mx:ViewStack id="myViewStack" 
> >         borderStyle="solid" 
> >         width="200"
> >         creationPolicy="all">
> > 
> >         <mx:Canvas id="search" 
> >             label="Search" >
> >             <mx:Label text="Search Screen"/>
> >         </mx:Canvas>
> > 
> >         <mx:Canvas id="custInfo" 
> >             label="Customer Info">
> >             <mx:Label text="Customer Info"/>
> >         </mx:Canvas>
> >     </mx:ViewStack>
> > 
> >     <mx:Button click="toSecond.play()" label="Play Effect" />
> > </mx:Application>
> > 
> > 
> > 
> > 
> >      
> 
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