Thanks Alex I started getting <cue value="20"/>
traced out but when I tried out trace(_slides[0].cue.(@value > 20).toXMLString()); is gives the same thing just prints an empty space. Shouldnt it return an XMLList with all nodes where value is greater than 20 ?? cheers firdosh On 2/14/07, Alex Harui <[EMAIL PROTECTED]> wrote:
Do not trust trace or toString() with XML. By default it tries to dump the text content of a XML or XMLList. Always debug by printing out the toXMLString(). HTH, -Alex ------------------------------ *From:* [email protected] [mailto:flexcompone [EMAIL PROTECTED] *On Behalf Of *Firdosh Tangri *Sent:* Wednesday, February 14, 2007 10:41 AM *To:* [email protected] *Subject:* [flexcomponents] XML query question I have a simple xml <slide id="366" frameRate="30" totalFrames="150" advance="auto" type="normal"> <cue value="20"/> <content url=" Slide1.swf"/> <slideTitle>1.Adobe Connect Solutions</slideTitle> <slideBackground index="1" frameToPlay="3" duration="00:10" showAfterFrame="0"/> <notes isHTML="true"> Few organizations are untouched by today's imperative to do business across geographies. </notes> </slide> I load it into an XMLList Object _slides when I do a trace([EMAIL PROTECTED]); // traces out 20 fine when I try trace(_slides[0].cue.(@value=='20')); or trace(_slides[0].cue.(@value=='"20")); or trace(_slides[0].cue.(@value=='20)); I get nothing ?? thanks cheers :) firdosh
