Firdosh,

 

When dealing with XML, you must also read the fine print.
XMLList.parent is null if the XMLList contains stuff from different
parents.

 

________________________________

From: [email protected]
[mailto:[EMAIL PROTECTED] On Behalf Of Firdosh Tangri
Sent: Wednesday, February 14, 2007 1:31 PM
To: [email protected]
Subject: Re: [flexcomponents] XML query question

 

hey all,
            I am tryin to follow the examples from the Prog in AS3 book
the XML ones 
var x:XML =
<employeeList>
<employee id="347">
<lastName>Zmed</lastName>
<firstName>Sue</firstName> 
<position>Data analyst</position>
</employee>
<employee id="348">
<lastName>McGee</lastName>
<firstName>Chuck</firstName>
<position>Jr. data analyst</position> 
</employee>
</employeeList>


x.employee.(@id == 347).lastName  // This is the lastName property of
the first
employee node. So far so good....

so now if I should do x.employee.(@id == 347).parent shouldnt I get the
parent Node as an XMLList 

like in my example for 

var cues:XMLList=(_slides.cue.(@value > previousCuePoint && @value <
video_HSlider.value)
 i get back
<cue value="20"/>
<cue value="68"/> 
<cue value="100"/>

so If i were to access a the sibling node say for value 20 I want to get
the content node the url attribute 

var cues:XMLList=(_slides.cue.(@value > previousCuePoint && @value <
video_HSlider.value).content // this would not work since it would look
for content as child node for cue 
( hope I am correct here ) . so if I shoudl say return the parent
shouldnt that return a XMLList of the parent nodes ??

<slide id="366" frameRate="30" totalFrames="150" advance="auto"
type="normal"> 
                 <cue value="20"/>
                 <content url="Slide1.swf"/>                         
                <slideTitle>1.Adobe Connect Solutions</slideTitle>

                <slideBackground index="1" frameToPlay="3"
duration="00:10" showAfterFrame="0"/>    
                <notes isHTML="true">                  
 </slide>


thanks for all the help :)
firdosh



 

Reply via email to