David Megginson writes: >Feel free to play with the sample tree and to compare it to the >non-billboarded tree. I don't know which approach would be better for >an entire forest: > >1. The non-billboarded tree has 18 vertices (or so), but doesn't > require any special dynamic transformation. > >2. The billboarded tree has only 4 vertices, but requires a > transformation based on the view matrix. > >Norm: which do you think would be more efficient for a forest of, say, >500 trees?
It probably depends ..... Hardware assisted OpenGL can be hard to predict But I am guessing you already know the answer, on your machine at least :-) Norman _______________________________________________ Flightgear-devel mailing list [EMAIL PROTECTED] http://mail.flightgear.org/mailman/listinfo/flightgear-devel
