> > void
> > readXML (istream &input, XMLVisitor &visitor, const string &path)
> > {
> > XML_Parser parser = XML_ParserCreate(0);
>
> > .......
>
> > XML_ParserFree(parser);
> > cout << "A-3" << endl;
> >
> > throw sg_io_exception("Problem reading file",
> > sg_location(path,
> > XML_GetCurrentLineNumber(parser),
>
>
> What happens to parser after the call to XML_ParserFree(parser)? Can it still
> be referenced after that?
>
> Dave
That's interesting. I wonder. Still, I think the problem is occurring earlier,
because for
some reason the check for input.good() is returning "bad". I have no idea why.
Jon
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