On Oct 30, 2009, at 1:35 PM, Matthias Melcher wrote: > so as long as there is one window visible, run() will not return. > > How about: > > while (myWindow->shown()) Fl::run();
That is almost the same as Fl::run() by itself. I want: while (myWindow (or any window) exists, shown or hidden) Fl::run(); Thanks, Harvey _______________________________________________ fltk mailing list [email protected] http://lists.easysw.com/mailman/listinfo/fltk
