Harvey Chapman wrote:
> Normally, I have "return Fl::run()" at the end of my programs. However,
> I'm currently writing an app that should appear and disappear
> periodically. Fl::run() does not work in this case because it exits when
> no more windows are visible. Is there a way to keep going as long as any
> window exists or perhaps as long as my main window exists?
>
> Something like...
>
> while (any_window_exists) wait(FOREVER);
>
> or
>
> // Not sure how this would work...
> Fl_Window *w;
> while (w_exists) wait(FOREVER);
Hmm, what do you mean with "exists", as opposed to "visible"? A window
that is hidden, does still exist as an object, until you delete it, and
you can't delete static objects until the program exits. But see below.
> Actually, I guess I could just do it the old fashioned way:
>
> bool quit = false;
> while (!quit) wait(FOREVER);
Matthias explained already how Fl::run() works.
Maybe you mean something like:
Fl_Window main_win (...);
// initialize program...
bool quit = false;
while (!quit) {
main_win.show();
Fl::run();
// determine how long to wait ...
if ( <end_of_program> )
quit = true;
else
sleep(10); // e.g. replace by your own logic
}
This would automatically raise the main window 10 seconds after the last
window (probably the main window?) has been closed and Fl::run() returned.
There's nothing wrong with calling Fl::run() more than once (in a loop).
Albrecht
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