Hello Jam,
Most of the typical FME list answerers are out partying tonight after
the first day of the FME Worldwide UC, no doubt talking about the
dramatic turn of events at the FME Idol competition which saw Peter
Laulund (on Ultraedit doing mapping files and Tcl) tie with
Jason Birch (on Workbench) in solving a relatively tough problem in
real-time in front of a live audience.
So I'll jump in.
You need a 2d point replacer transformer, just pop that down in
workbench between your source and destination. A coordinate system
setter for good measure to set a LL-83 (or whichever Lat/Long system
the data is in) woudl be good too. And remember that X is Longitude, Y
is Lat.
BTW one of the FME Idol completion was basically a more complex
version of your problem here...
Dale
> Hello,
>
> i have a simple file with this data, (only a few records):
>
> Name,Province,Region,CntryName,latitude,longitude
> Mlynsky Vrch,Ceske
> Budejovice,Jihocesky,Poland,48.7111889826538,14.7093636674568
> Stare Hute,Ceske
> Budejovice,Jihocesky,Poland,48.7199842819732,14.7127678490038
> Sejby,Ceske
>
> I try to transform it into a KML file but the KML file i obtain
> contents no placemarks, no coordinates for the points, only
> dedscriptions.
>
> I can not find how to say to FME that the csv-field-defined as
> longitude and latitude are the coordinates of a placemark, that's
> the main issue.
>
> If you know how to do that, please write a short step by step guide,
> i'm sure that it is a very simple question but i'm not able to find
> it at the moment.
>
> Thanks in advance,
>
> Jam
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