On Wed, 2004-05-26 at 10:08, James Earl wrote: > On Tue, 2004-05-25 at 18:14, Andreas L. Delmelle wrote: > > > Say you have a max record width (sum of all respective max field widths) of > > 65, then each column gets its width according to a calculation like > > > > [( proportional-width / 65 ) * remaining-table-width ] > > I'll post any success that I have!
I'm not sure if I'm doing this right... but the following gave acceptable results: Columns (max field length): 1. 20 2. 10 3. 5 4. 1 5. 11 6. 6 Total: 53 Calculations: 1. (20 / 53) * 33 = 12.5 (e.g. proportional-column-width(12.5)) 2. (10 / 53) * 43 = 8.1 3. (5 / 53) * 48 = 4.5 4. (1 / 53) * 52 = 0.9 5. (11 / 53) * 42 = 8.7 6. (6 / 53) * 47 = 5.3 I've just tried this once so far, but it worked great. I have two templates set up. Once exports xsl-fo, while the other one exports html. The PDF generated by FOP looks almost identical in terms of the column widths. I just need to take into account the max length of the column heading when it is larger than the column data. James --------------------------------------------------------------------- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
