After reading this over again I'm not sure you need to do the nested tables
after all. It looks like you want to print a new set of column headers at the
same point in time as when you want a new group header, and if that's the case
you can just create 2 rows inside one table-header. So I interpret your
algorithm needs to be explained like so:
1. For each set of "ROW" elements inside a unique grouping of child
"Focus" element values, create a table for that group where the "Focus" element
value and the column headers for each child element under ROW whose name is not
equal to "Focus" are placed into a table-header.
2. Within the group created in step 1, create table-rows for each ROW
Using XSLT 2.0 you can do something like this to accomplish said algorithm:
<for-each-group select="//ROW" group-by="Focus">
<table>
<table-header>
<table-row><table-cell><block><value-of
select="Focus"/></block></table-cell></table-row>
<table-row>
<for-each select="*[local-name() != 'Focus']>
// Create cells for column headers
</for-each>
</table-row>
</table-header>
<table-body>
<for-each select="current-group()">
<table-row>
// Create cells for columns
</table-row>
</for-each>
</table-body>
</table>
</for-each-group>
If you're using XSLT 1.0 you can still accomplish the same thing but it's more
difficult. Google for "XSLT Muenchian" to find examples.
From: Paige Balter [mailto:[EMAIL PROTECTED]
Sent: Tuesday, August 12, 2008 1:12 PM
To: [email protected]
Subject: Re: Repeating table/group headers on subsequent pages
That is an intriguing idea, Sean, and just might work, thank you!
Do you build your tables with For-each statements (e.g. <xsl:for-each
select=".//ROW">)? And how do you get the outer table's header to change with
each new grouping?
Thanks, again!
~Paige
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