Ups - sorry: "contains" instead of "substring" of course :/
Am 29.09.2013 um 17:47 schrieb Frank Hirsch <frank.hir...@mac.com>: > Right, not the right list… > But maybe a quick and simple solution: <xsl:for-each > select="//items/item[substr($theList,text()]"><xsl:for-each>? > > Am 29.09.2013 um 17:20 schrieb Glenn Adams <gl...@skynav.com>: > >> This question relates to XSLT, not XSL-FO or FOP, so this isn't really the >> right ML to post this. >> >> >> On Sun, Sep 29, 2013 at 12:23 AM, Bernard Giannetti >> <thebernmeis...@hotmail.com> wrote: >> Hi, >> >> I'm using FOP, embedded in a desktop application, to create PDFs from a >> single data XML file using an XSLT file. >> >> Say the data XML file is a list of items, for example: >> >> <items> >> <item> >> apple >> </item> >> <item> >> orange >> </item> >> <item> >> water melon >> </item> >> ... >> </items> >> >> I want to be able to tell the XSLT to only process specific items (say >> "apple" and "orange"). >> >> I've created a java.util.ArrayList and passed that to the transformer using >> setParameter( "theList", theList ). In the XSLT, when I use <xsl:value-of >> select="$theList" />, I'll get in the output [apple, orange]. Fair enough. >> >> However, what I really want (I think) is to take the array and iterate over >> it, calling a template for each item. Is this possible? >> >> From what I've managed to deduce from a lot of searching/reading is that >> it's possible even to pass in a Java object and somehow get XSLT to access >> that Java object. I'm not sure if that is overkill for what I want to do, >> but I cannot even achieve processing a list of items one by one. >> >> >> Thanks in advance, >> >> Bernard. >> >
