Each of the  pairs of non-rational conjugacy classes — the two containing 
elements of order 11 and the two containing elements of order 8 form a rational 
class (at least in the sense used by the GAP command) when combined. Hence the 
total of 8 (6 single conjugacy classes and 2 pairs).  See the GAP documentation 
under RationalClass and RationalClasses for details. 

> On 19 Aug 2017, at 16:06, johnathon simons <johnathonasim...@outlook.com> 
> wrote:
> 
> Dear Thomas,
> 
> 
> Thank you for your helpful comments on calculating the symmetrised structure 
> constant.
> 
> 
> Perhaps my understanding of rational classes is incorrect, but I have taken 
> it from this equivalence: 
> https://math.stackexchange.com/questions/218302/a-conjugacy-class-c-is-rational-iff-cn-in-c-whenever-c-in-c-and-n-is-co
> 
>> From my understanding of that, we would say a conjugacy class is rational if 
>> every entry of it in the character table is rational under the respective 
>> column. However, using my reasoning, if we look at M11, under the columns 8a 
>> and 8b it has entries of A = -sqrt(-2) and also underneath 11a and 11b it 
>> has entries B = (-1 - sqrt(-11)/2) both which are not rational and so that 
>> would mean M11 has only 6 rational classes (it has a total of 10 conjugacy 
>> classes)
> 
> 
> But, using the "RationalClasses" function on GAP we know that M11 has 8 
> rational classes.  I'm certain I am mistaken in my reasoning/interpretation 
> of the character table and would very much be appreciative of an explanation.
> 
> Essentially, all I am trying to do is find a triple of conjugacy classes 
> (that are rational) such that a triple (g_1, g_2, g_3) of elements  satisfies 
> the rigidity condition of Thompson to realize the group M11 as Galois over Q.
> 
> I am very much appreciative for all your help,
> 
> 
> John
> 
> 
> [https://cdn.sstatic.net/Sites/math/img/apple-touch-i...@2.png?v=4ec1df2e49b1]<https://math.stackexchange.com/questions/218302/a-conjugacy-class-c-is-rational-iff-cn-in-c-whenever-c-in-c-and-n-is-co>
> 
> A conjugacy class $C$ is rational iff $c^n\\in C$ whenever 
> ...<https://math.stackexchange.com/questions/218302/a-conjugacy-class-c-is-rational-iff-cn-in-c-whenever-c-in-c-and-n-is-co>
> math.stackexchange.com
> Let $C$ be a conjugacy class of the finite group $G$. Say that $C$ is 
> rational if for each character $\chi: G \rightarrow \mathbb C$ of $G$, for 
> each $c\in C$, we ...
> 
> 
> 
> 
> Sent from Outlook<http://aka.ms/weboutlook>
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