Am 09.06.2019 um 17:23 schrieb Ryan Joseph: > > >> On Jun 9, 2019, at 9:45 AM, Florian Klämpfl <[email protected]> wrote: >> >> And? It is obvious that FPC has to know what's the base type of a pointer >> else it couldn't do type checking. > > I think all he means is this: > > type > TInt = ^integer; > > procedure DoThis(i: TInt); > begin > end; > > var > a: ^integer; > begin > DoThis(a0); > > He just wants function parameters to declare the new pointer type inline.
Yes, but this has *nothing* to do with the output of -vp. Nothing. _______________________________________________ fpc-devel maillist - [email protected] http://lists.freepascal.org/cgi-bin/mailman/listinfo/fpc-devel
