In message <[EMAIL PROTECTED]>, you wrote:

> I don't believe the C89 standard doesn't have a way to test for NaN...

That is correct, but most actual C libraries DO provide some function
that will check for that condition.

> ... so, if we're talking portability here - you can't test for NaN.

Yes, but only if you are talking about ``portability'' in its purest
form.

In practice, you could easily construct an `is_this_a_NaN()' function
that would work on all platforms of interest.


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