In a script in am working on I need to find out the allocated
size of a sparse file.
The only command that comes to mind is "ls -lh"
The "du -h" command is not appropriate because it will show
the occupied size and not the allocated size.

I don't know how to parse out to the position in the output of that
"ls -lh" command to pickup the file size value.

Is there some other way to do this?
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