Glen writes:

"What evidence is there of degenerate ground states?"

The Hamiltonians for a logical operator like an OR gate need ground-state 
degeneracies for non-trivial applications.

Configuration Input0 Input1 -> Output
A 0 0 -> 0
B 0 1 -> 1
C 1 0 -> 1
D 1 1 -> 1

P(A) = P(B) = P(C) = P(D) = 0.25

If the probabilities (thus energies) were not balanced, then the OR gate could 
not be inverted in a fair way.   Excited eigenstates typically exist, but they 
would give configurations that were wrong like "D 0 0 -> 1".  Suppose one 
wanted to find the key for a complex encryption circuit.  A gate encoding that 
completely favored one gate, P(X) = 1, would not enable search. 

Marcus


 

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