Ralf Hemmecke <[email protected]> writes: > Dear Johannes, > > you have certainly looked at the implementation of = in Any. It says: > > x = y == (x.dm = y.dm) and EQ(x.ob, y.ob)$Lisp
didn't this come up some time ago already? Martin --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "FriCAS - computer algebra system" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/fricas-devel?hl=en -~----------~----~----~----~------~----~------~--~---
