-- 
Best regards,
Xiaojun Liu @ CAU
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在 2011年6月7日星期二,上午2:18,Ralf Hemmecke 写道:

> If I look at
> https://github.com/hemmecke/fricas-svn/blob/master/src/algebra/stream.spad.pamphlet#L552
> I read...
> 
> "A stream is an implementation of an infinite sequence ..."
> 
> The documentation clearly doesn't match the implementation.
> 
> Ralf
> 
> On 06/06/2011 08:05 PM, Martin Rubey wrote:
> > Xiaojun Liu<[email protected] (mailto:[email protected])> writes:
> > 
> > > Hi,
> > > 
> > >  I have two Stream of integers, called s1 and s2. I want to
> > > add their corresponding elements to form a new stream called s.
> > > I use map(f,x,y) to do this, but the result is unexpected if s1 is
> > > actually a finite stream, i.e.
> > > 
> > > (1) -> s1 := [i for i in 1..3] :: Stream INT
> > > 
> > >  (1) [1,2,3]
> > >  Type: Stream(Integer)
> > > (2) -> s2 := [j for j in 1..] :: Stream INT
> > > 
> > >  (2) [1,2,3,4,5,6,7,8,9,10,...]
> > >  Type: Stream(Integer)
> > > (3) -> map(+, s1, s2)
> > > 
> > >  (3) [2,4,6]
> > >  Type: Stream(Integer)
> > > 
> > > But I want the result : [2,4,6,4,5,6,7,8,9,10,...].
> > > Is there any simple way to do this?
> > > 
> > > Do I have to append s1 to a infinite stream by letting the rest
> > > elements all be 0 manually?
> > 
> > I think that's the way to go. It's not that bad:
> > 
> > [i+j for i in concat(s1, repeating [0]) for j in s2]
> > 
> > Martin
Oh, thanks ! 
> > 
> 
> 
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