在 2011年6月7日星期二，上午9:30，Bill Page 写道：
> > On 06/06/2011 08:05 PM, Martin Rubey wrote:
> > ...
> > Do I have to append s1 to a infinite stream by letting the rest
> > elements all be 0 manually?
> >
> > I think that's the way to go. It's not that bad:
> >
> > [i+j for i in concat(s1, repeating [0]) for j in s2]
>
> A more functional notation in the style of the original question would be:
>
> map(+,concat(s1,repeating [0]),s2)
Really helpful in my case, thx!
>
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