Ralf Hemmecke wrote:
>
> On 05/20/2014 03:14 AM, Waldek Hebisch wrote:
> > TeX exposens enough primitives to do this in a macro. One can try to
> > optimize breakpoints, for examples associating penalty with each
> > breakpoint (say, more nested operator has bigger penalty), but this
> > may be much more crude than for text (because no one expects formulas
> > to line up with margin). I do not know why breqn has such problems.
>
> I think, that is exactly what breqn is doing, but it's a bit more
> complicated. Things like \left(...\right) are usually internally put
> into an unbreakable \hbox by TeX (or LaTeX). breqn must count \left's
> and \right's so that these expressions possibly are kept together. You
> cannot simply put an equal penalty on every + to find a reasonable
> breakpoint.
>
> However, it's not even that easy. Think of something like
>
> a + \frac{b}{c} + \frac{d}{e} + f
>
> By which rule would you go if the denominator of c is too long to fit
>
> a + \frac{b}{c}
>
> onto one line, but if you break up c into 3 lines, say, and the
> numerator d into 3 lines then even f would fit into the line, i.e. best
> looking would be an expression that breaks inside the fractions.
> Breaking up c into only two lines would not achieve this.
>
> Fortunately, we don't have something like that in the output for the
> book, but I find the above problem hard to solve no matter whether in
> TeX or TeXFormat.
Sure, that is extra problem. But no reason to fail on long output.
In our context, long '\frac' simply should be linearized (turned
into '/'). The same with other operators. This requires some
amount of work, but IIUC breqn fails much earlier.
--
Waldek Hebisch
[email protected]
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