On 05/23/2014 07:26 PM, Waldek Hebisch wrote: > Ralf Hemmecke wrote: >> >> Let x be of type SExpression. I would like to test whether x is the Lisp >> value T. I can do this via >> >> foo(x: SExpression): Boolean == >> TRUE: SExpression := EQ(x,x)$Lisp >> x = TRUE > > I am affraid this is one of simplest ways.
I found out that currently also TRUE: SExpression := true pretend SExpression would work. There could also be something like TRUE: SExpression := NOT(convert([]$List(SExpression)))$Lisp I guess the first one is too dangerous and not future proof, right? What about the second? I'd be happy, to have access to a constant instead of having the need to call a function. Well, in my case it's certainly not too time critical, but anyway. Ralf -- You received this message because you are subscribed to the Google Groups "FriCAS - computer algebra system" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To post to this group, send email to [email protected]. Visit this group at http://groups.google.com/group/fricas-devel. For more options, visit https://groups.google.com/d/optout.
