On 12/10/2014 09:17 AM, Ralf Hemmecke wrote:
integrate(x^(1/3)/(3*x+1)^(1/3), x)
Would you be satisfied with what
integrate((x/(3*x+1))^(1/3), x)
returns?
Wow, I shall be satisfied with that. It's even better than Mathematica
(which returns a Hypergeometric function).
But a flaw is that the result is real only for x<-1/3. Although a simple
modification can make it valid for both x<-1/3 and x>0.
(Also, the merge of exponent here happen to be valid (in a point of view
of complex arithmetic)...)
BTW: Is sourceforge.net/p/fricas/bugs/ the proper place to report bug?
Yes. That's what http://fricas.sourceforge.net/ says.
Ralf
Seems the mailing list is much more active than there :-)
xyy
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