On 12/10/2014 09:17 AM, Ralf Hemmecke wrote:
integrate(x^(1/3)/(3*x+1)^(1/3), x)
Would you be satisfied with what

   integrate((x/(3*x+1))^(1/3), x)

returns?

Wow, I shall be satisfied with that. It's even better than Mathematica (which returns a Hypergeometric function). But a flaw is that the result is real only for x<-1/3. Although a simple modification can make it valid for both x<-1/3 and x>0. (Also, the merge of exponent here happen to be valid (in a point of view of complex arithmetic)...)


BTW: Is sourceforge.net/p/fricas/bugs/ the proper place to report bug?
Yes. That's what http://fricas.sourceforge.net/ says.

Ralf

Seems the mailing list is much more active than there :-)

xyy

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