Hello
It is possible to instantiate a class from a variable name - before PHP
5.3 even. I've been doing this with 5.2 in a project I'm working on.
I think the key thing is the syntax:
$table1 = new $originClass; // note no brackets
Hopefully that'll help!
Pete
On 4/24/08, *Denis Fohl* <[EMAIL PROTECTED]
<mailto:[EMAIL PROTECTED]>> wrote:
Hi all,
sorry i forgot the subject in my previous post :
i'm trying to implement a class to manage manytomany relationships
in backoffice, i'd like to standardize it for reusability.
I would like to pass to the constructor of my class the name of
the tables involved (destination table, origin table, intersection
table) and that it instantiate correspondings Zend_Db_Table objects.
So now is the question : how can i instantiate an object
(Zend_Db_Table here) with a variable classname :
function __construct ($originTable, $destinationTable) {
$table1 = new $originTable();
...
}
i can't find what i want on google (tried call_user_func but
that's not it).
This sounds similar to something I've been trying to do a while ago.
After reading a *lot* about this, I found out this was not possible
before PHP 5.3. I'm not sure exactly where I found that, but a good
starting point would be the comments on http://nl3.php.net/get-class .
Thanks.
Denis.
Best of luck,
--
Vincent
