I am on PHP 5.2.5 and for me it works to use: $fubar = new $class($params ...);
Cheers, Holger -----Original Message----- From: Pete Spicer [mailto:[EMAIL PROTECTED] Sent: Thursday, April 24, 2008 6:09 PM To: [email protected] Subject: Re: [fw-general] instantiate an object with a variable name for the class Hello It is possible to instantiate a class from a variable name - before PHP 5.3 even. I've been doing this with 5.2 in a project I'm working on. I think the key thing is the syntax: $table1 = new $originClass; // note no brackets Hopefully that'll help! Pete > > > On 4/24/08, *Denis Fohl* <[EMAIL PROTECTED] > <mailto:[EMAIL PROTECTED]>> wrote: > > Hi all, > > sorry i forgot the subject in my previous post : > > i'm trying to implement a class to manage manytomany relationships > in backoffice, i'd like to standardize it for reusability. > I would like to pass to the constructor of my class the name of > the tables involved (destination table, origin table, intersection > table) and that it instantiate correspondings Zend_Db_Table objects. > > So now is the question : how can i instantiate an object > (Zend_Db_Table here) with a variable classname : > > function __construct ($originTable, $destinationTable) { > > $table1 = new $originTable(); > ... > > } > > i can't find what i want on google (tried call_user_func but > that's not it). > > > This sounds similar to something I've been trying to do a while ago. > After reading a *lot* about this, I found out this was not possible > before PHP 5.3. I'm not sure exactly where I found that, but a good > starting point would be the comments on http://nl3.php.net/get-class . > > Thanks. > > Denis. > > > Best of luck, > > -- > Vincent
